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Explain the differences between string and &str
Can you tell me what is wrong with this code?
let mut text = ""; if text.is_empty() { let new_text = String::from("hello"); text = &new_text; } call_function(text);
The problem with your code is related to variable ownership and lifetime in Rust. When assigning
text = &new_text;
, you are trying to create a reference (&new_text
) to a variable new_text
that is created inside the if
block. This will lead to a problem because new_text
's scope is limited to the if
block and it will be dropped once the execution leaves this scope. The text
variable then ends up referencing a value that no longer exists.
A potential way to fix this is to make the new_text
variable outside of the if
block and assign the value inside the if
block:
Now, thelet mut text = String::new(); let mut new_text = String::new(); if text.is_empty() { new_text = String::from("hello"); text = new_text; } call_function(&text);
new_text
has a scope that extends to the end of the current function, not just the if
block, so text
will be a valid reference when it is passed into call_function
. The reference being passed to call_function
needs to be a &String
instead of String
.Can we use &str instead of string here?
Yes, you can use
str
instead of String
in certain cases, but the &str
type would need to refer to a string literal or a String
that lives long enough. Here's how you modify your initial code to use &str
:
This code works because the string "hello" is a string literal, which is stored directly in the compiled program, and its lifetime is the duration of the program. Hencelet mut text: &str = ""; if text.is_empty() { let new_text: &str = "hello"; text = new_text; } call_function(text);
text
refers to a valid string when you call call_function
.
But please note that if you tried to convert a String
variable to a &str inside the if
block, and assigned it to text
, you would run into ownership and lifetime issues, because the String
variable will be dropped at the end of the if
block.